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2+3x=2-12(x+9)
We move all terms to the left:
2+3x-(2-12(x+9))=0
We calculate terms in parentheses: -(2-12(x+9)), so:We get rid of parentheses
2-12(x+9)
determiningTheFunctionDomain -12(x+9)+2
We multiply parentheses
-12x-108+2
We add all the numbers together, and all the variables
-12x-106
Back to the equation:
-(-12x-106)
3x+12x+106+2=0
We add all the numbers together, and all the variables
15x+108=0
We move all terms containing x to the left, all other terms to the right
15x=-108
x=-108/15
x=-7+1/5
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