2+3r+1=3(-3r+3)+3(2+3r)

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Solution for 2+3r+1=3(-3r+3)+3(2+3r) equation: 



2+3r+1=3(-3r+3)+3(2+3r)

We move all terms to the left:

2+3r+1-(3(-3r+3)+3(2+3r))=0

We add all the numbers together, and all the variables

3r-(3(-3r+3)+3(3r+2))+2+1=0

We add all the numbers together, and all the variables

3r-(3(-3r+3)+3(3r+2))+3=0



We calculate terms in parentheses: -(3(-3r+3)+3(3r+2)), so:

3(-3r+3)+3(3r+2)

We multiply parentheses

-9r+9r+9+6

We add all the numbers together, and all the variables

15

Back to the equation:

-(15)



We add all the numbers together, and all the variables

3r-12=0

We move all terms containing r to the left, all other terms to the right

3r=12

r=12/3

r=4

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