2+3n=4+4(1+n)

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Solution for 2+3n=4+4(1+n) equation: 



2+3n=4+4(1+n)

We move all terms to the left:

2+3n-(4+4(1+n))=0

We add all the numbers together, and all the variables

3n-(4+4(n+1))+2=0



We calculate terms in parentheses: -(4+4(n+1)), so:

4+4(n+1)

determiningTheFunctionDomain
4(n+1)+4

We multiply parentheses

4n+4+4

We add all the numbers together, and all the variables

4n+8

Back to the equation:

-(4n+8)



We get rid of parentheses

3n-4n-8+2=0

We add all the numbers together, and all the variables

-1n-6=0

We move all terms containing n to the left, all other terms to the right

-n=6

n=6/-1

n=-6

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