2+3c=-3(-2c+6)

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Solution for 2+3c=-3(-2c+6) equation: 



2+3c=-3(-2c+6)

We move all terms to the left:

2+3c-(-3(-2c+6))=0



We calculate terms in parentheses: -(-3(-2c+6)), so:

-3(-2c+6)

We multiply parentheses

6c-18

Back to the equation:

-(6c-18)



We get rid of parentheses

3c-6c+18+2=0

We add all the numbers together, and all the variables

-3c+20=0

We move all terms containing c to the left, all other terms to the right

-3c=-20

c=-20/-3

c=6+2/3

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