2+3(z-3)=z+3z+6z

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Solution for 2+3(z-3)=z+3z+6z equation: 



2+3(z-3)=z+3z+6z

We move all terms to the left:

2+3(z-3)-(z+3z+6z)=0

We add all the numbers together, and all the variables

3(z-3)-(+10z)+2=0

We multiply parentheses

3z-(+10z)-9+2=0

We get rid of parentheses

3z-10z-9+2=0

We add all the numbers together, and all the variables

-7z-7=0

We move all terms containing z to the left, all other terms to the right

-7z=7

z=7/-7

z=-1

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