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2+3(x+1)=5(x+1)
We move all terms to the left:
2+3(x+1)-(5(x+1))=0
We multiply parentheses
3x-(5(x+1))+3+2=0
We calculate terms in parentheses: -(5(x+1)), so:We add all the numbers together, and all the variables
5(x+1)
We multiply parentheses
5x+5
Back to the equation:
-(5x+5)
3x-(5x+5)+5=0
We get rid of parentheses
3x-5x-5+5=0
We add all the numbers together, and all the variables
-2x=0
x=0/-2
x=0
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