2+3(4m-5)=-109

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Solution for 2+3(4m-5)=-109 equation: 



2+3(4m-5)=-109

We move all terms to the left:

2+3(4m-5)-(-109)=0

We add all the numbers together, and all the variables

3(4m-5)+111=0

We multiply parentheses

12m-15+111=0

We add all the numbers together, and all the variables

12m+96=0

We move all terms containing m to the left, all other terms to the right

12m=-96

m=-96/12

m=-8

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