2+3(3x-7)=9-4(3x+1)

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Solution for 2+3(3x-7)=9-4(3x+1) equation: 



2+3(3x-7)=9-4(3x+1)

We move all terms to the left:

2+3(3x-7)-(9-4(3x+1))=0

We multiply parentheses

9x-(9-4(3x+1))-21+2=0



We calculate terms in parentheses: -(9-4(3x+1)), so:

9-4(3x+1)

determiningTheFunctionDomain
-4(3x+1)+9

We multiply parentheses

-12x-4+9

We add all the numbers together, and all the variables

-12x+5

Back to the equation:

-(-12x+5)



We add all the numbers together, and all the variables

9x-(-12x+5)-19=0

We get rid of parentheses

9x+12x-5-19=0

We add all the numbers together, and all the variables

21x-24=0

We move all terms containing x to the left, all other terms to the right

21x=24

x=24/21

x=1+1/7

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