2+3(3-3b)=38

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Solution for 2+3(3-3b)=38 equation:



2+3(3-3b)=38
We move all terms to the left:
2+3(3-3b)-(38)=0
We add all the numbers together, and all the variables
3(-3b+3)+2-38=0
We add all the numbers together, and all the variables
3(-3b+3)-36=0
We multiply parentheses
-9b+9-36=0
We add all the numbers together, and all the variables
-9b-27=0
We move all terms containing b to the left, all other terms to the right
-9b=27
b=27/-9
b=-3

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