2+3(2x-5)=3-7(3-x)

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Solution for 2+3(2x-5)=3-7(3-x) equation: 



2+3(2x-5)=3-7(3-x)

We move all terms to the left:

2+3(2x-5)-(3-7(3-x))=0

We add all the numbers together, and all the variables

3(2x-5)-(3-7(-1x+3))+2=0

We multiply parentheses

6x-(3-7(-1x+3))-15+2=0



We calculate terms in parentheses: -(3-7(-1x+3)), so:

3-7(-1x+3)

determiningTheFunctionDomain
-7(-1x+3)+3

We multiply parentheses

7x-21+3

We add all the numbers together, and all the variables

7x-18

Back to the equation:

-(7x-18)



We add all the numbers together, and all the variables

6x-(7x-18)-13=0

We get rid of parentheses

6x-7x+18-13=0

We add all the numbers together, and all the variables

-1x+5=0

We move all terms containing x to the left, all other terms to the right

-x=-5

x=-5/-1

x=+5

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