2+2x-3/2x+3=3x+4/x+2

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Solution for 2+2x-3/2x+3=3x+4/x+2 equation: 



2+2x-3/2x+3=3x+4/x+2

We move all terms to the left:

2+2x-3/2x+3-(3x+4/x+2)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: x+2)!=0

x∈R



We add all the numbers together, and all the variables

2x-3/2x-(3x+4/x+2)+5=0

We get rid of parentheses

2x-3/2x-3x-4/x-2+5=0

We calculate fractions


2x-3x+(-3x)/2x^2+(-8x)/2x^2-2+5=0

We add all the numbers together, and all the variables

-1x+(-3x)/2x^2+(-8x)/2x^2+3=0

We multiply all the terms by the denominator


-1x*2x^2+(-3x)+(-8x)+3*2x^2=0

Wy multiply elements

-2x^3+6x^2+(-3x)+(-8x)=0

We get rid of parentheses

-2x^3+6x^2-3x-8x=0

We do not support expression: x^3

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