2+2(z-7)=-3(3+z)+4z-9

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Solution for 2+2(z-7)=-3(3+z)+4z-9 equation: 



2+2(z-7)=-3(3+z)+4z-9

We move all terms to the left:

2+2(z-7)-(-3(3+z)+4z-9)=0

We add all the numbers together, and all the variables

2(z-7)-(-3(z+3)+4z-9)+2=0

We multiply parentheses

2z-(-3(z+3)+4z-9)-14+2=0



We calculate terms in parentheses: -(-3(z+3)+4z-9), so:

-3(z+3)+4z-9

We add all the numbers together, and all the variables

4z-3(z+3)-9

We multiply parentheses

4z-3z-9-9

We add all the numbers together, and all the variables

z-18

Back to the equation:

-(z-18)



We add all the numbers together, and all the variables

2z-(z-18)-12=0

We get rid of parentheses

2z-z+18-12=0

We add all the numbers together, and all the variables

z+6=0

We move all terms containing z to the left, all other terms to the right

z=-6

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