2+2(n-6)=4(n+1)

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Solution for 2+2(n-6)=4(n+1) equation: 



2+2(n-6)=4(n+1)

We move all terms to the left:

2+2(n-6)-(4(n+1))=0

We multiply parentheses

2n-(4(n+1))-12+2=0



We calculate terms in parentheses: -(4(n+1)), so:

4(n+1)

We multiply parentheses

4n+4

Back to the equation:

-(4n+4)



We add all the numbers together, and all the variables

2n-(4n+4)-10=0

We get rid of parentheses

2n-4n-4-10=0

We add all the numbers together, and all the variables

-2n-14=0

We move all terms containing n to the left, all other terms to the right

-2n=14

n=14/-2

n=-7

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