2+2(5y-2)=-2(2y-8)+6y

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Solution for 2+2(5y-2)=-2(2y-8)+6y equation: 



2+2(5y-2)=-2(2y-8)+6y

We move all terms to the left:

2+2(5y-2)-(-2(2y-8)+6y)=0

We multiply parentheses

10y-(-2(2y-8)+6y)-4+2=0



We calculate terms in parentheses: -(-2(2y-8)+6y), so:

-2(2y-8)+6y

We add all the numbers together, and all the variables

6y-2(2y-8)

We multiply parentheses

6y-4y+16

We add all the numbers together, and all the variables

2y+16

Back to the equation:

-(2y+16)



We add all the numbers together, and all the variables

10y-(2y+16)-2=0

We get rid of parentheses

10y-2y-16-2=0

We add all the numbers together, and all the variables

8y-18=0

We move all terms containing y to the left, all other terms to the right

8y=18

y=18/8

y=2+1/4

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