2+1.25f=10-2.75f2+1.25f

Solution for 2+1.25f=10-2.75f2+1.25f equation:

2+1.25f=10-2.75f^2+1.25f

We move all terms to the left:

2+1.25f-(10-2.75f^2+1.25f)=0

We get rid of parentheses

2.75f^2-1.25f+1.25f-10+2=0

We add all the numbers together, and all the variables

2.75f^2-8=0

a = 2.75; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·2.75·(-8)
Δ = 88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{88}=\sqrt{4*22}=\sqrt{4}*\sqrt{22}=2\sqrt{22}$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{22}}{2*2.75}=\frac{0-2\sqrt{22}}{5.5}
=-\frac{2\sqrt{22}}{5.5}
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{22}}{2*2.75}=\frac{0+2\sqrt{22}}{5.5}
=\frac{2\sqrt{22}}{5.5}
$