2+1.25f=10-2.75f2

Solution for 2+1.25f=10-2.75f2 equation:

2+1.25f=10-2.75f^2

We move all terms to the left:

2+1.25f-(10-2.75f^2)=0

We get rid of parentheses

2.75f^2+1.25f-10+2=0

We add all the numbers together, and all the variables

2.75f^2+1.25f-8=0

a = 2.75; b = 1.25; c = -8;
Δ = b2-4ac
Δ = 1.252-4·2.75·(-8)
Δ = 89.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.25)-\sqrt{89.5625}}{2*2.75}=\frac{-1.25-\sqrt{89.5625}}{5.5}
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.25)+\sqrt{89.5625}}{2*2.75}=\frac{-1.25+\sqrt{89.5625}}{5.5}
$