If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2+(x/10)=(2/5)
We move all terms to the left:
2+(x/10)-((2/5))=0
We add all the numbers together, and all the variables
(+x/10)+2-((+2/5))=0
We get rid of parentheses
x/10+2-((+2/5))=0
We calculate fractions
5x^2/()+2+()/()=0
We add all the numbers together, and all the variables
5x^2/()+3=0
We multiply all the terms by the denominator
5x^2+3*()=0
We add all the numbers together, and all the variables
5x^2=0
a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{10}=0$
| 1.5t=6t+7 | | -2s=24 | | 2/5x-2=8 | | 2*(9x-4)-7+3*(6-5x)=18 | | 3x/2+15=5 | | 1/2x=160 | | y/3-6=4+6 | | 11^x=69 | | 1/8x=40 | | x^2-5x-5=-2x+5 | | 11x=69 | | 37=t4 | | 12(3x-4)+16=40 | | 2(7x-55=7x-20-2x | | -9+2*(5x-4)=21 | | 2(x^2)-7=21 | | 2(3x+1)-2x=14 | | 8m+21=-11 | | 2m+11=5m+2 | | x^{5}-x=0. | | 3(3n-4)+6n=72 | | x^2+11+26=2 | | 3x-7=-(x-5) | | -7v+9=2 | | 12+4x=6•2x | | 4(m+5)-19=17 | | t-12/2=t/2-3 | | -75+7y=-9+6y | | 2xx2-7=21 | | 3/7=1/7+3x | | -3/2=1/5v=2/3 | | 0.6x^2+1.4x-4.8=0 |