2+(m+4)=10-2(m+2)

Solution for 2+(m+4)=10-2(m+2) equation:

2+(m+4)=10-2(m+2)

We move all terms to the left:

2+(m+4)-(10-2(m+2))=0

We get rid of parentheses

m-(10-2(m+2))+4+2=0


We calculate terms in parentheses: -(10-2(m+2)), so:

10-2(m+2)

determiningTheFunctionDomain
-2(m+2)+10

We multiply parentheses

-2m-4+10

We add all the numbers together, and all the variables

-2m+6

Back to the equation:

-(-2m+6)


We add all the numbers together, and all the variables

m-(-2m+6)+6=0

We get rid of parentheses

m+2m-6+6=0

We add all the numbers together, and all the variables

3m=0

m=0/3

m=0