2+(3-2x)-(1-x)=3x-2(x-3)

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Solution for 2+(3-2x)-(1-x)=3x-2(x-3) equation: 



2+(3-2x)-(1-x)=3x-2(x-3)

We move all terms to the left:

2+(3-2x)-(1-x)-(3x-2(x-3))=0

We add all the numbers together, and all the variables

(-2x+3)-(-1x+1)-(3x-2(x-3))+2=0

We get rid of parentheses

-2x+1x-(3x-2(x-3))+3-1+2=0



We calculate terms in parentheses: -(3x-2(x-3)), so:

3x-2(x-3)

We multiply parentheses

3x-2x+6

We add all the numbers together, and all the variables

x+6

Back to the equation:

-(x+6)



We add all the numbers together, and all the variables

-1x-(x+6)+4=0

We get rid of parentheses

-1x-x-6+4=0

We add all the numbers together, and all the variables

-2x-2=0

We move all terms containing x to the left, all other terms to the right

-2x=2

x=2/-2

x=-1

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