2+(2x+3)(x-2)=2(x+1)(x-4)+18

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Solution for 2+(2x+3)(x-2)=2(x+1)(x-4)+18 equation: 



2+(2x+3)(x-2)=2(x+1)(x-4)+18

We move all terms to the left:

2+(2x+3)(x-2)-(2(x+1)(x-4)+18)=0

We multiply parentheses ..

(+2x^2-4x+3x-6)-(2(x+1)(x-4)+18)+2=0



We calculate terms in parentheses: -(2(x+1)(x-4)+18), so:

2(x+1)(x-4)+18

We multiply parentheses ..

2(+x^2-4x+x-4)+18

We multiply parentheses

2x^2-8x+2x-8+18

We add all the numbers together, and all the variables

2x^2-6x+10

Back to the equation:

-(2x^2-6x+10)



We get rid of parentheses

2x^2-2x^2-4x+3x+6x-6-10+2=0

We add all the numbers together, and all the variables

5x-14=0

We move all terms containing x to the left, all other terms to the right

5x=14

x=14/5

x=2+4/5

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