2*2+2x=2(15-x)+3*2

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Solution for 2*2+2x=2(15-x)+3*2 equation: 



2*2+2x=2(15-x)+3*2

We move all terms to the left:

2*2+2x-(2(15-x)+3*2)=0

We add all the numbers together, and all the variables

2x-(2(-1x+15)+3*2)+2*2=0

We add all the numbers together, and all the variables

2x-(2(-1x+15)+3*2)+4=0



We calculate terms in parentheses: -(2(-1x+15)+3*2), so:

2(-1x+15)+3*2

We add all the numbers together, and all the variables

2(-1x+15)+6

We multiply parentheses

-2x+30+6

We add all the numbers together, and all the variables

-2x+36

Back to the equation:

-(-2x+36)



We get rid of parentheses

2x+2x-36+4=0

We add all the numbers together, and all the variables

4x-32=0

We move all terms containing x to the left, all other terms to the right

4x=32

x=32/4

x=8

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