2*(b+1)=3*(b-1)

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Solution for 2*(b+1)=3*(b-1) equation: 



2(b+1)=3(b-1)

We move all terms to the left:

2(b+1)-(3(b-1))=0

We multiply parentheses

2b-(3(b-1))+2=0



We calculate terms in parentheses: -(3(b-1)), so:

3(b-1)

We multiply parentheses

3b-3

Back to the equation:

-(3b-3)



We get rid of parentheses

2b-3b+3+2=0

We add all the numbers together, and all the variables

-1b+5=0

We move all terms containing b to the left, all other terms to the right

-b=-5

b=-5/-1

b=+5

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