2*(7t-5)-4*(2t-3)=0

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Solution for 2*(7t-5)-4*(2t-3)=0 equation:


Simplifying
2(7t + -5) + -4(2t + -3) = 0

Reorder the terms:
2(-5 + 7t) + -4(2t + -3) = 0
(-5 * 2 + 7t * 2) + -4(2t + -3) = 0
(-10 + 14t) + -4(2t + -3) = 0

Reorder the terms:
-10 + 14t + -4(-3 + 2t) = 0
-10 + 14t + (-3 * -4 + 2t * -4) = 0
-10 + 14t + (12 + -8t) = 0

Reorder the terms:
-10 + 12 + 14t + -8t = 0

Combine like terms: -10 + 12 = 2
2 + 14t + -8t = 0

Combine like terms: 14t + -8t = 6t
2 + 6t = 0

Solving
2 + 6t = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 6t = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 6t = 0 + -2
6t = 0 + -2

Combine like terms: 0 + -2 = -2
6t = -2

Divide each side by '6'.
t = -0.3333333333

Simplifying
t = -0.3333333333

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