2*(10*x)+2(15*2*x*1/3)=40*x

Solution for 2*(10*x)+2(15*2*x*1/3)=40*x equation:

2(10x)+2(15*2x*1/3)=40x

We move all terms to the left:

2(10x)+2(15*2x*1/3)-(40x)=0

We add all the numbers together, and all the variables

210x+2(+15*2x*1/3)-40x=0

We add all the numbers together, and all the variables

170x+2(+15*2x*1/3)=0

We multiply parentheses

60x^2+170x=0

a = 60; b = 170; c = 0;
Δ = b2-4ac
Δ = 1702-4·60·0
Δ = 28900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28900}=170$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(170)-170}{2*60}=\frac{-340}{120}
=-2+5/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(170)+170}{2*60}=\frac{0}{120}
=0
$