2(z-9)=5(z+1)-8

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Solution for 2(z-9)=5(z+1)-8 equation:


Simplifying
2(z + -9) = 5(z + 1) + -8

Reorder the terms:
2(-9 + z) = 5(z + 1) + -8
(-9 * 2 + z * 2) = 5(z + 1) + -8
(-18 + 2z) = 5(z + 1) + -8

Reorder the terms:
-18 + 2z = 5(1 + z) + -8
-18 + 2z = (1 * 5 + z * 5) + -8
-18 + 2z = (5 + 5z) + -8

Reorder the terms:
-18 + 2z = 5 + -8 + 5z

Combine like terms: 5 + -8 = -3
-18 + 2z = -3 + 5z

Solving
-18 + 2z = -3 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-18 + 2z + -5z = -3 + 5z + -5z

Combine like terms: 2z + -5z = -3z
-18 + -3z = -3 + 5z + -5z

Combine like terms: 5z + -5z = 0
-18 + -3z = -3 + 0
-18 + -3z = -3

Add '18' to each side of the equation.
-18 + 18 + -3z = -3 + 18

Combine like terms: -18 + 18 = 0
0 + -3z = -3 + 18
-3z = -3 + 18

Combine like terms: -3 + 18 = 15
-3z = 15

Divide each side by '-3'.
z = -5

Simplifying
z = -5

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