2(z-6)=4(z+2)-12

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Solution for 2(z-6)=4(z+2)-12 equation:


Simplifying
2(z + -6) = 4(z + 2) + -12

Reorder the terms:
2(-6 + z) = 4(z + 2) + -12
(-6 * 2 + z * 2) = 4(z + 2) + -12
(-12 + 2z) = 4(z + 2) + -12

Reorder the terms:
-12 + 2z = 4(2 + z) + -12
-12 + 2z = (2 * 4 + z * 4) + -12
-12 + 2z = (8 + 4z) + -12

Reorder the terms:
-12 + 2z = 8 + -12 + 4z

Combine like terms: 8 + -12 = -4
-12 + 2z = -4 + 4z

Solving
-12 + 2z = -4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-12 + 2z + -4z = -4 + 4z + -4z

Combine like terms: 2z + -4z = -2z
-12 + -2z = -4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-12 + -2z = -4 + 0
-12 + -2z = -4

Add '12' to each side of the equation.
-12 + 12 + -2z = -4 + 12

Combine like terms: -12 + 12 = 0
0 + -2z = -4 + 12
-2z = -4 + 12

Combine like terms: -4 + 12 = 8
-2z = 8

Divide each side by '-2'.
z = -4

Simplifying
z = -4

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