2(z-5)=9z+4*

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Solution for 2(z-5)=9z+4* equation: 



2(z-5)=9z+4*

We move all terms to the left:

2(z-5)-(9z+4*)=0

We add all the numbers together, and all the variables

2(z-5)-(+9z)=0

We multiply parentheses

2z-(+9z)-10=0

We get rid of parentheses

2z-9z-10=0

We add all the numbers together, and all the variables

-7z-10=0

We move all terms containing z to the left, all other terms to the right

-7z=10

z=10/-7

z=-1+3/7

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