2(z-4)=4z+10

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Solution for 2(z-4)=4z+10 equation: 



2(z-4)=4z+10

We move all terms to the left:

2(z-4)-(4z+10)=0

We multiply parentheses

2z-(4z+10)-8=0

We get rid of parentheses

2z-4z-10-8=0

We add all the numbers together, and all the variables

-2z-18=0

We move all terms containing z to the left, all other terms to the right

-2z=18

z=18/-2

z=-9

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