2(z-4)+2(3+z)=-46

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Solution for 2(z-4)+2(3+z)=-46 equation: 



2(z-4)+2(3+z)=-46

We move all terms to the left:

2(z-4)+2(3+z)-(-46)=0

We add all the numbers together, and all the variables

2(z-4)+2(z+3)-(-46)=0

We add all the numbers together, and all the variables

2(z-4)+2(z+3)+46=0

We multiply parentheses

2z+2z-8+6+46=0

We add all the numbers together, and all the variables

4z+44=0

We move all terms containing z to the left, all other terms to the right

4z=-44

z=-44/4

z=-11

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