2(z-3)=4(z+3)-10

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Solution for 2(z-3)=4(z+3)-10 equation:


Simplifying
2(z + -3) = 4(z + 3) + -10

Reorder the terms:
2(-3 + z) = 4(z + 3) + -10
(-3 * 2 + z * 2) = 4(z + 3) + -10
(-6 + 2z) = 4(z + 3) + -10

Reorder the terms:
-6 + 2z = 4(3 + z) + -10
-6 + 2z = (3 * 4 + z * 4) + -10
-6 + 2z = (12 + 4z) + -10

Reorder the terms:
-6 + 2z = 12 + -10 + 4z

Combine like terms: 12 + -10 = 2
-6 + 2z = 2 + 4z

Solving
-6 + 2z = 2 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-6 + 2z + -4z = 2 + 4z + -4z

Combine like terms: 2z + -4z = -2z
-6 + -2z = 2 + 4z + -4z

Combine like terms: 4z + -4z = 0
-6 + -2z = 2 + 0
-6 + -2z = 2

Add '6' to each side of the equation.
-6 + 6 + -2z = 2 + 6

Combine like terms: -6 + 6 = 0
0 + -2z = 2 + 6
-2z = 2 + 6

Combine like terms: 2 + 6 = 8
-2z = 8

Divide each side by '-2'.
z = -4

Simplifying
z = -4

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