2(z-2)=5(z+1)-3

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Solution for 2(z-2)=5(z+1)-3 equation:


Simplifying
2(z + -2) = 5(z + 1) + -3

Reorder the terms:
2(-2 + z) = 5(z + 1) + -3
(-2 * 2 + z * 2) = 5(z + 1) + -3
(-4 + 2z) = 5(z + 1) + -3

Reorder the terms:
-4 + 2z = 5(1 + z) + -3
-4 + 2z = (1 * 5 + z * 5) + -3
-4 + 2z = (5 + 5z) + -3

Reorder the terms:
-4 + 2z = 5 + -3 + 5z

Combine like terms: 5 + -3 = 2
-4 + 2z = 2 + 5z

Solving
-4 + 2z = 2 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-4 + 2z + -5z = 2 + 5z + -5z

Combine like terms: 2z + -5z = -3z
-4 + -3z = 2 + 5z + -5z

Combine like terms: 5z + -5z = 0
-4 + -3z = 2 + 0
-4 + -3z = 2

Add '4' to each side of the equation.
-4 + 4 + -3z = 2 + 4

Combine like terms: -4 + 4 = 0
0 + -3z = 2 + 4
-3z = 2 + 4

Combine like terms: 2 + 4 = 6
-3z = 6

Divide each side by '-3'.
z = -2

Simplifying
z = -2

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