2(z-1)=4(z+3)-4

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Solution for 2(z-1)=4(z+3)-4 equation:


Simplifying
2(z + -1) = 4(z + 3) + -4

Reorder the terms:
2(-1 + z) = 4(z + 3) + -4
(-1 * 2 + z * 2) = 4(z + 3) + -4
(-2 + 2z) = 4(z + 3) + -4

Reorder the terms:
-2 + 2z = 4(3 + z) + -4
-2 + 2z = (3 * 4 + z * 4) + -4
-2 + 2z = (12 + 4z) + -4

Reorder the terms:
-2 + 2z = 12 + -4 + 4z

Combine like terms: 12 + -4 = 8
-2 + 2z = 8 + 4z

Solving
-2 + 2z = 8 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-2 + 2z + -4z = 8 + 4z + -4z

Combine like terms: 2z + -4z = -2z
-2 + -2z = 8 + 4z + -4z

Combine like terms: 4z + -4z = 0
-2 + -2z = 8 + 0
-2 + -2z = 8

Add '2' to each side of the equation.
-2 + 2 + -2z = 8 + 2

Combine like terms: -2 + 2 = 0
0 + -2z = 8 + 2
-2z = 8 + 2

Combine like terms: 8 + 2 = 10
-2z = 10

Divide each side by '-2'.
z = -5

Simplifying
z = -5

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