2(z-1)=32

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Solution for 2(z-1)=32 equation: 



2(z-1)=32

We move all terms to the left:

2(z-1)-(32)=0

We multiply parentheses

2z-2-32=0

We add all the numbers together, and all the variables

2z-34=0

We move all terms containing z to the left, all other terms to the right

2z=34

z=34/2

z=17

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