2(z+6)=3z+12

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Solution for 2(z+6)=3z+12 equation:



2(z+6)=3z+12
We move all terms to the left:
2(z+6)-(3z+12)=0
We multiply parentheses
2z-(3z+12)+12=0
We get rid of parentheses
2z-3z-12+12=0
We add all the numbers together, and all the variables
-z=0
z=0/-1
z=0

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