2(z+5)=3(4z+2)-1

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Solution for 2(z+5)=3(4z+2)-1 equation: 



2(z+5)=3(4z+2)-1

We move all terms to the left:

2(z+5)-(3(4z+2)-1)=0

We multiply parentheses

2z-(3(4z+2)-1)+10=0



We calculate terms in parentheses: -(3(4z+2)-1), so:

3(4z+2)-1

We multiply parentheses

12z+6-1

We add all the numbers together, and all the variables

12z+5

Back to the equation:

-(12z+5)



We get rid of parentheses

2z-12z-5+10=0

We add all the numbers together, and all the variables

-10z+5=0

We move all terms containing z to the left, all other terms to the right

-10z=-5

z=-5/-10

z=1/2

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