2(z+5)+5(z+2)=10(2-1)

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Solution for 2(z+5)+5(z+2)=10(2-1) equation: 



2(z+5)+5(z+2)=10(2-1)

We move all terms to the left:

2(z+5)+5(z+2)-(10(2-1))=0

We add all the numbers together, and all the variables

2(z+5)+5(z+2)-(101)=0

We add all the numbers together, and all the variables

2(z+5)+5(z+2)-101=0

We multiply parentheses

2z+5z+10+10-101=0

We add all the numbers together, and all the variables

7z-81=0

We move all terms containing z to the left, all other terms to the right

7z=81

z=81/7

z=11+4/7

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