2(z+2)+4=10+2z-2

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Solution for 2(z+2)+4=10+2z-2 equation:


Simplifying
2(z + 2) + 4 = 10 + 2z + -2

Reorder the terms:
2(2 + z) + 4 = 10 + 2z + -2
(2 * 2 + z * 2) + 4 = 10 + 2z + -2
(4 + 2z) + 4 = 10 + 2z + -2

Reorder the terms:
4 + 4 + 2z = 10 + 2z + -2

Combine like terms: 4 + 4 = 8
8 + 2z = 10 + 2z + -2

Reorder the terms:
8 + 2z = 10 + -2 + 2z

Combine like terms: 10 + -2 = 8
8 + 2z = 8 + 2z

Add '-8' to each side of the equation.
8 + -8 + 2z = 8 + -8 + 2z

Combine like terms: 8 + -8 = 0
0 + 2z = 8 + -8 + 2z
2z = 8 + -8 + 2z

Combine like terms: 8 + -8 = 0
2z = 0 + 2z
2z = 2z

Add '-2z' to each side of the equation.
2z + -2z = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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