2(z+1)-4(z-4)=29(z=5)

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Solution for 2(z+1)-4(z-4)=29(z=5) equation: 



2(z+1)-4(z-4)=29(z=5)

We move all terms to the left:

2(z+1)-4(z-4)-(29(z)=0

We multiply parentheses

2z-4z-(29z+2+16=0

We add all the numbers together, and all the variables

-2z-(29z+2+16=0

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