2(z+1)+12z=2(7z+2)

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Solution for 2(z+1)+12z=2(7z+2) equation: 



2(z+1)+12z=2(7z+2)

We move all terms to the left:

2(z+1)+12z-(2(7z+2))=0

We add all the numbers together, and all the variables

12z+2(z+1)-(2(7z+2))=0

We multiply parentheses

12z+2z-(2(7z+2))+2=0



We calculate terms in parentheses: -(2(7z+2)), so:

2(7z+2)

We multiply parentheses

14z+4

Back to the equation:

-(14z+4)



We add all the numbers together, and all the variables

14z-(14z+4)+2=0

We get rid of parentheses

14z-14z-4+2=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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