2(y-8)-5=-3(-8y+2)-4y

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Solution for 2(y-8)-5=-3(-8y+2)-4y equation: 



2(y-8)-5=-3(-8y+2)-4y

We move all terms to the left:

2(y-8)-5-(-3(-8y+2)-4y)=0

We multiply parentheses

2y-(-3(-8y+2)-4y)-16-5=0



We calculate terms in parentheses: -(-3(-8y+2)-4y), so:

-3(-8y+2)-4y

We add all the numbers together, and all the variables

-4y-3(-8y+2)

We multiply parentheses

-4y+24y-6

We add all the numbers together, and all the variables

20y-6

Back to the equation:

-(20y-6)



We add all the numbers together, and all the variables

2y-(20y-6)-21=0

We get rid of parentheses

2y-20y+6-21=0

We add all the numbers together, and all the variables

-18y-15=0

We move all terms containing y to the left, all other terms to the right

-18y=15

y=15/-18

y=-5/6

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