2(y-7)-10=12-4y

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Solution for 2(y-7)-10=12-4y equation: 



2(y-7)-10=12-4y

We move all terms to the left:

2(y-7)-10-(12-4y)=0

We add all the numbers together, and all the variables

2(y-7)-(-4y+12)-10=0

We multiply parentheses

2y-(-4y+12)-14-10=0

We get rid of parentheses

2y+4y-12-14-10=0

We add all the numbers together, and all the variables

6y-36=0

We move all terms containing y to the left, all other terms to the right

6y=36

y=36/6

y=6

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