2(y-6)=3(y-4)-4

Solution for 2(y-6)=3(y-4)-4 equation:

2(y-6)=3(y-4)-4

We move all terms to the left:

2(y-6)-(3(y-4)-4)=0

We multiply parentheses

2y-(3(y-4)-4)-12=0


We calculate terms in parentheses: -(3(y-4)-4), so:

3(y-4)-4

We multiply parentheses

3y-12-4

We add all the numbers together, and all the variables

3y-16

Back to the equation:

-(3y-16)


We get rid of parentheses

2y-3y+16-12=0

We add all the numbers together, and all the variables

-1y+4=0

We move all terms containing y to the left, all other terms to the right

-y=-4

y=-4/-1

y=+4