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2(y-5)=3(-y+5)
We move all terms to the left:
2(y-5)-(3(-y+5))=0
We add all the numbers together, and all the variables
2(y-5)-(3(-1y+5))=0
We multiply parentheses
2y-(3(-1y+5))-10=0
We calculate terms in parentheses: -(3(-1y+5)), so:We get rid of parentheses
3(-1y+5)
We multiply parentheses
-3y+15
Back to the equation:
-(-3y+15)
2y+3y-15-10=0
We add all the numbers together, and all the variables
5y-25=0
We move all terms containing y to the left, all other terms to the right
5y=25
y=25/5
y=5
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