2(y-5)-8=-7(-3y+4)-y

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Solution for 2(y-5)-8=-7(-3y+4)-y equation: 



2(y-5)-8=-7(-3y+4)-y

We move all terms to the left:

2(y-5)-8-(-7(-3y+4)-y)=0

We multiply parentheses

2y-(-7(-3y+4)-y)-10-8=0



We calculate terms in parentheses: -(-7(-3y+4)-y), so:

-7(-3y+4)-y

We add all the numbers together, and all the variables

-1y-7(-3y+4)

We multiply parentheses

-1y+21y-28

We add all the numbers together, and all the variables

20y-28

Back to the equation:

-(20y-28)



We add all the numbers together, and all the variables

2y-(20y-28)-18=0

We get rid of parentheses

2y-20y+28-18=0

We add all the numbers together, and all the variables

-18y+10=0

We move all terms containing y to the left, all other terms to the right

-18y=-10

y=-10/-18

y=5/9

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