2(y-5)-6=-2(-9y+4)-4y

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Solution for 2(y-5)-6=-2(-9y+4)-4y equation: 



2(y-5)-6=-2(-9y+4)-4y

We move all terms to the left:

2(y-5)-6-(-2(-9y+4)-4y)=0

We multiply parentheses

2y-(-2(-9y+4)-4y)-10-6=0



We calculate terms in parentheses: -(-2(-9y+4)-4y), so:

-2(-9y+4)-4y

We add all the numbers together, and all the variables

-4y-2(-9y+4)

We multiply parentheses

-4y+18y-8

We add all the numbers together, and all the variables

14y-8

Back to the equation:

-(14y-8)



We add all the numbers together, and all the variables

2y-(14y-8)-16=0

We get rid of parentheses

2y-14y+8-16=0

We add all the numbers together, and all the variables

-12y-8=0

We move all terms containing y to the left, all other terms to the right

-12y=8

y=8/-12

y=-2/3

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