2(y-4)=8(y-1)-6y

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Solution for 2(y-4)=8(y-1)-6y equation: 



2(y-4)=8(y-1)-6y

We move all terms to the left:

2(y-4)-(8(y-1)-6y)=0

We multiply parentheses

2y-(8(y-1)-6y)-8=0



We calculate terms in parentheses: -(8(y-1)-6y), so:

8(y-1)-6y

We add all the numbers together, and all the variables

-6y+8(y-1)

We multiply parentheses

-6y+8y-8

We add all the numbers together, and all the variables

2y-8

Back to the equation:

-(2y-8)



We get rid of parentheses

2y-2y+8-8=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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