2(y-4)=6y+6-2(-4y-1)

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Solution for 2(y-4)=6y+6-2(-4y-1) equation: 



2(y-4)=6y+6-2(-4y-1)

We move all terms to the left:

2(y-4)-(6y+6-2(-4y-1))=0

We multiply parentheses

2y-(6y+6-2(-4y-1))-8=0



We calculate terms in parentheses: -(6y+6-2(-4y-1)), so:

6y+6-2(-4y-1)

determiningTheFunctionDomain
6y-2(-4y-1)+6

We multiply parentheses

6y+8y+2+6

We add all the numbers together, and all the variables

14y+8

Back to the equation:

-(14y+8)



We get rid of parentheses

2y-14y-8-8=0

We add all the numbers together, and all the variables

-12y-16=0

We move all terms containing y to the left, all other terms to the right

-12y=16

y=16/-12

y=-1+1/3

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