2(y-4)=3(y+2)+8

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Solution for 2(y-4)=3(y+2)+8 equation: 


Simplifying
2(y + -4) = 3(y + 2) + 8

Reorder the terms:
2(-4 + y) = 3(y + 2) + 8
(-4 * 2 + y * 2) = 3(y + 2) + 8
(-8 + 2y) = 3(y + 2) + 8

Reorder the terms:
-8 + 2y = 3(2 + y) + 8
-8 + 2y = (2 * 3 + y * 3) + 8
-8 + 2y = (6 + 3y) + 8

Reorder the terms:
-8 + 2y = 6 + 8 + 3y

Combine like terms: 6 + 8 = 14
-8 + 2y = 14 + 3y

Solving
-8 + 2y = 14 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-8 + 2y + -3y = 14 + 3y + -3y

Combine like terms: 2y + -3y = -1y
-8 + -1y = 14 + 3y + -3y

Combine like terms: 3y + -3y = 0
-8 + -1y = 14 + 0
-8 + -1y = 14

Add '8' to each side of the equation.
-8 + 8 + -1y = 14 + 8

Combine like terms: -8 + 8 = 0
0 + -1y = 14 + 8
-1y = 14 + 8

Combine like terms: 14 + 8 = 22
-1y = 22

Divide each side by '-1'.
y = -22

Simplifying
y = -22

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