2(y-4)=20+2y-12

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Solution for 2(y-4)=20+2y-12 equation: 



2(y-4)=20+2y-12

We move all terms to the left:

2(y-4)-(20+2y-12)=0

We add all the numbers together, and all the variables

2(y-4)-(2y+8)=0

We multiply parentheses

2y-(2y+8)-8=0

We get rid of parentheses

2y-2y-8-8=0

We add all the numbers together, and all the variables

-16!=0

There is no solution for this equation

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