2(y-3)-4y=12

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Solution for 2(y-3)-4y=12 equation: 



2(y-3)-4y=12

We move all terms to the left:

2(y-3)-4y-(12)=0

We add all the numbers together, and all the variables

-4y+2(y-3)-12=0

We multiply parentheses

-4y+2y-6-12=0

We add all the numbers together, and all the variables

-2y-18=0

We move all terms containing y to the left, all other terms to the right

-2y=18

y=18/-2

y=-9

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